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Flagsmith lets you manage feature flags and remote config across web, mobile and server side applications. Deliver true Continuous Integration. Get builds out faster. Control who has access to new features. We're Open Source.

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Celery is an asynchronous task queue/job queue based on distributed message passing.

Which is more popular?
Based on our record, Flagsmith should be more popular than Celery Project. It has been mentioned 13 times since March 2021.
Website, pricing, platforms and company facts side by side.
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| Website | flagsmith.com | celeryproject.org |
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| Company | 2018 | — |
| Listed in |
What each product offers, as listed by its team.


Possible disadvantages
An editorial look at what each product does well and who it suits.


Overall verdict
Why this product is good
Recommended for
No analysis of Celery Project yet.
How often each product is chosen within a category, 0–100% relative to the other.


Share your experience with using Flagsmith and Celery Project. For example, how are they different and which one is better?
External articles and on-site reviews we used to compare the two products.


BlogBackSign inBlogThe 8 best free and open-source feature flag servicesPosted byThe best open-source feature flag tools1. PostHogWhat is PostHog?Supported librariesHow much does it cost?2. UnleashWhat is...
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Recommendations tracked on public social media and blogs since March 2021.


Considering all these points, the team at Flagsmith has developed a feature flag management platform Flagsmith and made it open source. The core functionality is open and you can check out the GitHub repository here. I have utilized and... - Source: dev.to / over 2 years ago
Flagsmith - Release features with confidence; manage feature flags across web, mobile, and server side applications. Use our hosted API, deploy to your own private cloud, or run on-premise. - Source: dev.to / almost 4 years ago
Flagsmith is written in Django and is open source as well: https://flagsmith.com. Source: over 4 years ago
How can I test if a task (task_id) is still processed in celery? I have the following scenario:. Source: over 4 years ago
I recently integrated celery (django-celery to be more specific) in one of my applications. I have a model in the application as follows. Source: over 4 years ago
I am trying to write a small application that receives video files, and convert them to a uniform format after they have been uploaded (thus added to the database). I have searched the web for the best solution for this, and have decided... Source: over 4 years ago
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