Graphing x^x on desmos.com makes it look as though the value is always greater than 1/2. Source: 10 months ago
=) I've posted a link to the desmos.com page with the data that used to create the graph above in the first reply to the post. =). Source: 10 months ago
It might help to graph the function, for example using desmos.com. Source: 10 months ago
Many answers can be checked numerically, even if only for a special case. There are also some sites that will solve certain types of problems, for example https://www.integral-calculator.com/. Graphing also sometimes helps, desmos.com. Source: 11 months ago
It might clarify your thinking to plot the two curves on desmos.com. You can also use the plots to check your work. Source: 11 months ago
Try playing around with this function on desmos.com and see what you can come up with. Hope this was helpful. :). Source: 11 months ago
It might clarify your thinking to graph the two functions (and help to check your work). On desmos.com, you can graph multiple functions in the same graph. Source: 11 months ago
Just go on desmos.com, know a fair bit about functions, and get to making whatever you want. You can put a transparent image on the graph if you need something to trace, just fiddle with it till it works. Source: 11 months ago
I wrote this post, because graph creator on desmos.com draws a circle for function x^2+y^2=1, and I thought it shouldn't, because if you'll count x and y separatley (and combine them), you'll get 3/4 of the circle. You can't get that 4th part of the circle, using this approach. On the other hand, equation can be true in the points (-x; -y). So I was confused by all this. Source: 12 months ago
It might help you to graph the equation, for example using desmos.com. If you do that, you will see that on every interval [0,a] there are greater values, and on every [-a,0] there are smaller values. If you simply equate the first derivative to zero, you will find that 0 is an inflection point--not an extreme. Source: 12 months ago
You might want to graph f(x), for example using desmos.com. Source: 12 months ago
Draw lots of pictures, and practice neat handwriting. Do all of the suggested practice problems. Know your unit circle like you know your own deepest fears. Use graphing tools like desmos.com to graph the original function AND it's derivative on the same coordinate plane and explain the patterns you observe between the two. Source: 12 months ago
I tried plotting it on desmos.com, but it doesn't look right, so I'm guessing this set only consists of numbers and not intervals:. Source: about 1 year ago
To help understand the problem, you might graph it (for example, using desmos.com) and/or compute a few actual values (for very negative values). Source: about 1 year ago
Check out geogebra.org and desmos.com and find those online communities, and *thank you.* I'm going to be so bold as to assume you want to make the topics make more sense to people than they usually do, and perhaps get more of them passing the courses? Source: about 1 year ago
Also, you can check your answer numerically by computing the values for some x's close to zero. You could also check by graphing the expression, for example at desmos.com. Source: about 1 year ago
It might help to graph the equations, for example using desmos.com (you can graph both expressions on the same graph). Both expressions seem to have the same slope at zero, of about 2 units. Source: about 1 year ago
[When you are learning how to graph the function, or transformation of the log function, you can use desmos.com to play around and to check your answers]. Source: over 1 year ago
My suggestion is to ignore all the math aspects about it and open desmos.com write "sin(x+k)", click the k and start playing, add 2, multiply by 2 etc. And see what happens. Source: over 1 year ago
Since the range of sin() is [-1,1], you might think that one possibility would be to let the transformed y = 4sin(x). However, this would not change the zeroes--the zeroes would still be {0, pi, 2pi,...}, i.e. k*pi, which doesn't fit the second condition given. In order to make the zeroes be k*pi/2, you might try 4sin(2x), so now for a zero value 2x = k*pi. To check this, it might be worthwhile to use a graphing... Source: over 1 year ago
You might try graphing it, for example using the tool at desmos.com. You might graph just the polynomial, or use abs() for absolute value. Source: over 1 year ago
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